Calculate the acceleration of an apple of mass 200gm.

The acceleration will vary with height.

Explanation:

According to the gravitational law the acceleration of a small body will be

g=GM/D^2

=(6.67×10^−(11))(6×10^(24))÷(6.4×10^6)^2

9.8m/s^2

The acceleration of an apple of 200 gram(assumed to be near the surface of Earth.) will be approximately 9.8 m per second square.

Acceleration of Earth can be calculated by this method.

According to the Newton's third law the force acting on that will be same as the force acting on the Apple. Let the mass of earth be M and the acceleration be A .and the mass of apple be m and acceleration of apple will be g.

Force on Apple = Force on earth

MG=mg

(6×10^(24))G=(0.2)×9.8

G=3.2667×10^(−25)m/s^2

hope it helped. :)

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