One length of a rectangular garden lies along a patio wall however the rest of the garden is enclosed by 36 feet of fencing if the length of the garden is twice it's with what is the area of the garden

162 feet²

Explanation:

One length of a rectangular garden lies along a patio wall. However, the rest of the garden is enclosed by 36 feet of fencing. If the length of the garden is twice its width, what is the area of the garden?

Solution:

Let x represent the length of the garden and y represent the width of the garden. Since the length of the garden is twice its width, hence:

x = 2y

Since 36 feet of fencing was used to enclose the rest of the building:

x + y + y = 36

x + 2y = 36

Substitute x = 2y:

2y + 2y = 36

4y = 36

y = 36 / 4

y = 9 feet

Substitute y = 9 to find x:

x = 2y = 2(9) = 18 feet

Therefore the length of the fence is 18 feet and the width is 9 feet.

The area of the garden = length * width = 18 feet * 9 feet = 162 feet²

it would be