Solve: X= 4+(4x-4)
0 x = 2
O x = 10
x = 2 or x = 10
o no real solution

x = 0

Explanation:

To solve, simplify, then isolate "x" (bring all "x" to the left).

x = 4 + (4x - 4)                Remove brackets

x = 4 + 4x - 4                 Collect like terms

x = 4 - 4 + 4x                  4 - 4 = 0, or nothing

x = 4x                             Bring "x" to the left

x - 4x = 4x - 4x              Subtract 4x on both sides

-3x = 0                           Get rid of multiplying by "-3".

      Divide both sides by -3

x = 0

Check the

Substitute x = 0 into the original equation. Remember to follow BEDMAS order.

x = 4 + (4x - 4)

0 = 4 + (4*0 - 4)        Solve multiplication in brackets first

0 = 4 + (0 - 4)            Subtract inside brackets

0 = 4 + (-4)                Adding a negative is the same as subtracting

0 = 4 - 4                    Subtract

0 = 0                         Same answer

LS = RS                     Left side equals right side

This solution is correct.

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