Which option identifies the obesity factor at work in the following scenario?

clarissa and her family live in a poor area of town and often struggle with getting dinner every night. when they can, they eat at all-you-can-eat restaurants and fast food places with large servings.

portion control
genetics
serving size distortion
demographics

Demographics.

Explanation:

When it comes to Clarissa and her family, they belong to the group that is not wealthy. Wealth can contribute to obesity factors and health, as they can have sources to feed well and they can count on the doctor, if something goes wrong. That is not the case for Clarissa and her family as they are struggling to have any type of dinner. Eating huge portions of foods at the end of the day is a terrible way to eat. People who do that are more prone to suffering from obesity and cardiovascular diseases.

The answer is: serving size distortion

Explanation:

Obesity is one of the common medical conditions that is increasing worldwide. It is the condition of having too much (excess amount) fat in the body. Its common contributing factors are: genetics, metabolic rate, food frequency, diet composition, etc.

In the case of Clarissa and her family, they are living in a poor area of town. This doesn't necessarily mean that they're poor. So, demographics doesn't play as an obesity factor. The situation also didn't mention anything about her family's genes on obesity. Portion control refers to how a person pays attention to the portions of the food he/she eats. Thus, this is not an obesity factor.

Serving size distortion refers to large serving sizes that are considered normal for people. In the case of Clarissa and her family, eating eat-all-you-can restaurants and fast food places with large servings is very normal for them. If they keep on consuming large amounts of food over time, then they'd surely become obese, provided that calorie-in is greater than calorie-out.

Thus, this makes "serving size distortion" as the answer.

answer; the above statement is (true);