In humans, the abo blood type is under control of autosomal multiple alleles. red-green colorblindness is a recessive x-linked trait. if two parents who are both type a and have normal vision produce a son who is colorblind and type o, what is the probability that their next child will be a female who has normal vision and is type o?

1/8

Explanation:

Father: normal vision, type A

Mother: normal vision, type A

They can only produce a colourblind son if female is the carrier for it:

         XC      Xc

XC  XCXC  XCXc

Y     XCY    XcY

XcY son will be colorblind. Hence father has XCY genotype and mother has XCXc genotype for vision.

They can only produce type O son if both of them are heterozygous for type A:

    A    O

A  AA  AO

O  AO  OO

OO son will have type O blood. Hence both father and mother have AO genotype for blood type.

Probability of having a female child=1/2

Probability of having a normal vision female child = 1 since in the first punnett square it has been shown that all female children have normal vision ( half are carriers )

Probability of having type O child = 1/4

Probability of having a female child with normal vision and type O blood = 1/2 * 1 * 1/4 = 1/8

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the answer should be true