what is the equation of the line that is parallel to the line y- 1 = 4(x+3) and passes through the point (4,32)

Explanation:

y-1 = 4(x+3)

Put this into slope intercept form y=mx+b

y-1=4x+12

y =4x+13

the slope is 4

parallel lines have same slope so you want

equation for line with slope m=4

through (4,32)

y=4x+b using (4,32) for (x,y) solve for b

32=4(4)+b

32=16+b

16=b

your equation is

y = 4x + 16

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