5. how fast did the shoes travel? (4 points) a. from where the shoes spilled (48°n, 161°w) to where they first made landfall (49°n, 126°w), how many kilometers did they travel? how many days did they take to travel that distance? (you can use november 30 as the date found). what was their rate of travel in kilometers per hour? 188 days to travel b. from where the shoes spilled (48°n, 161°w) to where they were found in 1996 (54°n, 133°w), how many kilometers did they travel? how many days did they take to travel that distance (use april 30 as the date found)? what was their rate of travel in kilometers per hour?

a) d = 35.0143 Km

t = 188 days

v = 7.76*10⁻³ Km/h

b) d = 28.6356 Km

t = 2165 days

v = 5.51*10-4 Km/h

Explanation:

a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49°N, 126°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((49-48)²+(126-161)²) = 35.0143 Km

How many days did they take to travel that distance? (You can use November 30 as the date found).  

From May 27, 1990 to November 30, 1990 we have

t = 5 days + (30 days/month)*(3 months) + (31 days/month)*(3 months) = 188 days

⇒   t = 188 days = (188 days)*(24 hours/day) = 4512 hours

What was their rate of travel in kilometers per hour?  

We use the equation

v = d/t   ⇒   v =  35.0143 Km/ 4512 h

⇒   v = 7.76*10⁻³ Km/h

b. From where the shoes spilled (48°N, 161°W) to where they were found in 1996 (54°N, 133°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((54-48)²+(133-161)²) = 28.6356 Km

How many days did they take to travel that distance (use April 30 as the date found)?  

From May 27, 1990 to April 30, 1996 we have

t = 5 days + (30 days/month)*(4 months) + (31 days/month)*(6 months) + 29 days + (365 days/ year)*(4 years)+ (366 days/ year)*(1 year)= 2165 days

⇒   t = 2165 days = (2165 days)*(24 hours/day) = 51960 hours

What was their rate of travel in kilometers per hour?

We use the equation

v = d/t   ⇒   v =  28.6356 Km/ 51960 h

⇒   v = 5.51*10-4 Km/h