Calculate and compare the amount of energy retrieved by the ocean and by the atmosphere. assume that the radius of the area is 1 m, and the density of seawater is 1028 kg m-3 and of air is 1.29 kg m-3. also, assume that the mean flow in the atmosphere is 10 m s-1 whereas that of the ocean is 1 m s-1.

for atmosphere K.E. = 0.5 × 1.29 × 10²

for atmosphere K.E. = 64.5 J

so we can say atmosphere is moving faster

and  amount of energy is significantly less than that is possessed by ocean of same volume

Explanation:

given data

radius of the area = 1 m

density of seawater = 1028 kg/m³

density of air = 1.29 kg/m³

mean flow atmosphere = 10 m/s

mean flow ocean = 1 m/s

to find out

Calculate and compare the amount of energy retrieved by the ocean and by the atmosphere

solution

we know that here kinetic energy is express as

K.E. = 0.5 × m× v²

here m is mass and v is velocity

but we take m = dv and where d is density and v is volume  

so

K.E. = 0.5 × dv × v²     1

and here we know side is 1 m

so volume will be =  1 m³

and dv is given = 1028 for ocean and 1.29 for atmosphere

so from equation 1

for ocean K.E. = 0.5 × 1028 × 1²

for ocean K.E. = 514 J

and

for atmosphere K.E. = 0.5 × 1.29 × 10²

for atmosphere K.E. = 64.5 J

so we can say atmosphere is moving faster

and  amount of energy is significantly less than that is possessed by ocean of same volume

c. seafloor spreading occurs.

d. crust becomes molten rock.

e. denser plates slide under lighter plates.