Find the volume of a frustum of a right pyramid whose lower base is a square with a side 5 in. and whose upper base is a square with a side 3 in., and whose altitude is 12 in. round your answer to the nearest whole number

The volume of a frustum of a pyramid is given as: Volume = h/3 [ A1 + A2 + √(A1 x A2) ] where h is the height, A1 is the area of the larger base and A2 is the smaller area. We are given all of the dimensions needed thus we can solve for the volume.

Volume = h/3 [ A1 + A2 + √(A1 x A2) ]
A1 = 5^2 = 25 in
A2 = 3^2 = 9 in

Volume = (12/3) [ 25 + 9 + √(25 x 9) ]
Volume = 196 in^2

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