How many gallons each of 25% alcohol and 5% alcohol should be mixed to obtain 20 gallons of 12% alcohol?

Should've put this in mathematics, you know? But don't worry, mistakes happen!

Though, in order to do this problem, we need to add 20 for the total gallon.

Let's use X for a placeholder to determine the amount, as the gallon of 25% alcohol and percentages can be in decimal forms. It'd be 0.25x gallons worth of alcohol afterwards. We then add 20-x gallons to 5% of alcohol, which is 0.05(20-x).

This would then allow us to find the sum of 20 gallons to 20% of alcohol, containing at least 0.2(20) gallons of the alcohol.

We'd then be able to develop this equation;

0.25x + 0.05(20-x) = 0.2(20).

And then so on the sequence continues...

0.25x + 1 - 0.05x = 4

0.2x = 3

x = 3/0.2

We'd then be able to come to a conclusion that;

1. X equals 15 gallons of 25% alcohol

2. 20-x equals 5 gallons of 5% alcohol.

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