The male and female guests attending patricia's party were surveyed to see if they drove to the party or did not drive. the data is displayed in the table below: male female drove to the party 26 24 did not drive to the party 34 116 if a guest is chosen at random from this group, what are the chances of choosing a guest who is male and did not drive to the party?

Gotcha covered.

The question asks for a random guest chosen randomly; so we know that there are a total of 200 guests. I got 200 by adding both male and female drivers and non-drivers.

Specifically, the question asks for male non-drivers. There are 34 male non-drivers out of 200 total guests.

Picking a male non-driver out of total guests results in this fraction: 34/200

We can simplify this fraction by dividing both sides by 2 since it can divide both numbers.

Once we do that, we get 17/100.

A percent is a number out of 100 and we know that number. It's 17, so we can say there's 17% a male non-driver would be picked out of the guests.

Hope this helped. If you have any questions, leave a comment. Good luck!