If employee a logged 120 hours of travel in four years and employee b logged hours of travel at a 20% higher rate, how many more hours did employee b have than employee a after 1.5 years?

Employee A in 4 years logged travel hours of = 120
Percentage more of travel hours logged by Employee B in 4 years = 20%
Then
Amount of travel hours logged by employee b in 4 years = (120/100) * 120
                                                                                           = 12 * 12
                                                                                           = 144 hours
Then amount of travel hours logged by Employee B after 1.5 years = (144/4) * 1.5
                                                                                                             = 216/4
                                                                                                             = 54 hours
Amount of travel hours logged by Employee A after 1.5 years = (120/4) * 1.5
                                                                                                  = 180/4
                                                                                                 = 45 hours.
Number of hours that Employee B had
than Employee A after 1.5 years = (54 - 45) hours
                                                     = 9 hours
So emplyee B had logged 9 hours more than Employee A after 1.5 years.

Okay, biology isn't exactly my strongest subject (it never has been), but i'm pretty sure the answer is nucleotides. dna is made up of nucleotides. each nucleotide contains a phosphate group, a sugar group, and a nitrogen base. there are four different nitrogen bases: adenine (a), thymine (t), guanine (g), and cytosine (c). a always pairs with t, and g always pairs with c.