Given the Boolean expression for F(A, B,C) F(AB, C) = AB+ ABC
. How many binary input comibinations are there for the output funtion F(A, B,C) to be 1

No of variables in Boolean expression is 3 i.e A,B,C

Number of input combinations.

It will follow the octal table.

000

001

010

011

100

101

110

110

We know the rule .

So

no of outputs which are 1=8-1=7

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hope this is what you're talking about