A 40-mm-diameter solid steel shaft, used as a torque transmitter, is replaced with a hollow shaft having a 40-mm outer diameter and a 36-mm inner diameter. If both materials have the same strength, what is the percentage reduction in torque transmission

65.61%

Explanation:

we have the following information to answer this question

diameter of the solid steel shaft = 40 mm

outer diametr of the hollow shaft = 40mm

inner diametr pf the hollow shaft = 36mm

= (40³ - (40⁴-36⁴)/40)/40³ * 100

= (40³ - 22009.6)/40³ * 100

= 41990.4/64000 * 100

= 0.6561 x 100

= 65.61%

percentage reduction in torque transmission = 65.61%

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