A heat rate of 3 kW is conducted through a section of an insulating materials of cross-sectional area 10 m^2 and thickness 2.5 cm. If the inner (hot) surface temperature is 415°C and the thermal conductivity of the material is 0.2 W/m*k , what is the outer surface temperature?

The outer surface temperature is .

Explanation:

Given: Heat = 3 kW (1 kW = 1000 W) = 3000 W

Area = 10

Length = 2.5 cm (1 cm = 0.01 m) = 0.025 m

Thermal conductivity = 0.2 W/m K

Temperature (inner) =

Formula used is as follows.

where,

K = thermal conductivity

A = area

L = length

= inner surface temperature

= outer surface temperature

Substitute the values into above formula as follows.

Thus, we can conclude that the outer surface temperature is .

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