Engineering, 17.05.2021 17:50 proxydayz
A 2.00 kg piece of aluminum metal at 75.0 °C is placed in 6.00 liters (= 6.00 kg) of water at 35.0 °C. Determine the final temperature .
Answers: 3
= mass of water = (Density)(Volume) = (1000 kg/m³)(1 L)(0.001 m³/1 L)
= mass of auminum piece = 2 kg
= specific heat capacity of water = 4200 J/kg.°C
= specific heat capacity of aluminum = 897 J/kg.°C
= Change in Temperature of Water = T - 35°C
= Change in Temperature of Aluminum Piece = 75°C - T
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A 2.00 kg piece of aluminum metal at 75.0 °C is placed in 6.00 liters (= 6.00 kg) of water at 35.0 °...
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