A refrigerator operating on the Carnot cycle is used to make ice. Water freezing at 32oF is the cold reservoir. Heat is rejected to a river at 72oF. Determine the work required to freeze 2000 lbm of ice if the energy required to freeze ice is 144 Btu/lbm. What is the power input required in kW and hp is this operation is carried out in 1 hour? [20] Hint: use the max. possible COP equations.

Explanation:

From the given information:

Water freezing temp.

Heat rejected temp

Recall that:

The coefficient of performance is:

Again:

The efficiency given by COP can be represented by:

Finally; the power input in an hour can be determined by using the formula:

In hp; since 1 kW = 1.34102 hp

6.86kW will be = (6.86 × 1.34102) hp

= 9.199 hp

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answer:

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explanation: