consider a stead flow ideal carnot cycle using steam as the working fluid in which the high temperature constant pressure heat addition process starts with a saturated liquid and ends with a saturated vapor. plot this cycle in t-s coordinates showing the steam dome. calculate the thermal efficiency for this cycle if the pressure of the high temperature steam is 6 mpa and the low temperature heat rejection process occurs at 300 k.

45.32%

Explanation:

Given data:

pressure of high temperature steam = 6 MPa

low temperature heat rejection process ( Tr )  = 300 k

A) plot of cycle in t-s coordinates showing steam dome

attached below

B) Calculate thermal efficiency

thermal efficiency = 1 - (Tr / Tsat )

Tsat = 275.59°C  ≈  548.59 K  ( from steam table at Pa = 6 MPa )

back to equation 1

1 - (300 / 548.59 )

1 - 0.5468 = 0.4532 = 45.32%

this is true

explanation:

i looked it up

answer:

an example of solubility is salt or sugar dissolving in water.

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