The operator of a CNC machine gets paid $60/hour. It takes him 9 mini to load and unload a part (i. e. handling time), and 4 mini to change the cutting tool (which has Taylor coefficients of 0.251 and 900 m/min)|. When he runs the spindle at 900 rpm it finishes a part in 11 mini. His cutting tool costs him $95 each and he is able to machine 80 parts| before having to replace the tool. He wants to know if he can save money by running the spindle at 1400 rpm. What is the cost per part at 900 rpm and at 1400 rpm? C = vT^n rightarrow T_2/T_1 = (C/v_2)^1/n/(C/v_1)^1/n = (v_1/v_2)^1/n

answer:

can you answer my question?

explanation:

answer:

clock

explanation:

always running (on) sing each hour (chime) and the clock face (front)

answer:

me yeah

explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)