Pt 1. Amanda lifts a crate into the back of her truck. She exerts a force of 200N distance of 1.2m. Calculate the amount of work (joules) done on the crate. Pt 2. Amanda then used an inclined plane to push the same crate into the truck She exerts a force of 77.5N a distance of 3.1m. What is the work (joules) done

Answer (Part 1):

620 joules

Explanation:

Work is done when force is applied on an object over a distance. It is measured in joules.

Formula

Thus, Work = Force x distance

Since, Work = ? (unknown value)

Given:

Force = 200N

Distance = 1.2 meters

So,

Work = 200N x 3.1 meters

= 620 joules

Thus, Amanda did a work of 620 joules on the crate.

Answer (Part 2):

240.25 joules

Explanation:

Work is done when force is applied on an object over a distance. It is measured in joules.

Formula

Thus, Work = Force x distance

Since, Work = ? (unknown value)

Given:

Force = 77.5N

Distance = 3.1 meters

So,

Work = 77.5N x 3.1 meters

= 240.25 joules

Thus, Amanda did a work of 240.25 joules on the crate.

Hope this helps! :)

twist boundary

explanation:

unlike the threaded fasteners which are used to clamp the machine members, power screws are used to transmit power. common applications of power screws are: screw jacks: to lift weight. lead screw of lathe: for axial movement of tool and its precise positioning.