cylindrical specimen of this alloy 32 mm in diameter and 188 mm long is to be pulled in tension. Assume a value of 0.34 for Poisson's ratio. Calculate the stress (in MPa) necessary to cause a 0.0105 mm reduction in diameter.

The stress required to cause a reduction of 0.0105mm on the alloy is 68.9MPa

Data Given;

The transverse strain of the cylindrical alloy is the ratio between the reduction in diameter to the actual diameter

The longitudinal strain is the ratio between the transverse strain to the Poisson's ratio.

Using the strain-stress graph of a cylindrical alloy, we would find the strain of 0.00097 around the stress of 68.9MPa

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The answer is below

Explanation:

The poison ratio is given by the formula:

We then locate the strain of 9.65 * 10⁻⁴ on the stress-strain curve, this gives a stress of 68.9 MPa

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