Use the Intermediate Value Theorem to show that there is a root of the given equation in the specified interval. Ex = 6 − 5x, (0, 1) The equation ex = 6 − 5x is equivalent to the equation f(x) = ex − 6 + 5x = 0. F(x) is continuous on the interval [0

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Answer :

F(0) = -5  < 0

F(1) = e - 1 > 0

since the functions : f(0) and f(1) have opposite signs then there is a 'c' whereby F(c) = 0 ( intermediate value theorem fulfilled )

Hence there is a root in the given equation :

Explanation:

using Intermediate value Theorem

If F(x) is continuous and f(a) and f(b) have opposite signs then there will be a'c'E (a,b)  whereby F(c) = 0

given equation :   on (0,1)

and F(x) =

This shows that the F(x) is continuous on (0,1)

F(0) =  = -5 which is < 0

F(1) = = e -1 > 0  and e = 2.7182

since the functions : f(0) and f(1) have opposite signs then there is a 'c' whereby F(c) = 0 ( intermediate value theorem fulfilled )

Hence there is a root in the given equation :

answer:

try looking it up that is always

explanation: