A 15.00 mL sample of a solution of H2SO4 of unknown concentration was titrated with 0.3200M NaOH. the titration required 21.30 mL of the base. Assuming complete neutralization of the acid, 1) What was the normality of the acid solution?
2) What was the molarity of the acid solution?

a. 0.4544 N

b.

Explanation:

For computing the normality and molarity of the acid solution first we need to do the following calculations

The balanced reaction

= 0.27264 g

= 0.006816 mol

Now

Moles of needed  is

= 0.003408 mol

= 0.333984 g

Now based on the above calculation

a. Normality of acid is

= 0.4544 N

b. And, the acid solution molarity is

= 0.00005112

=

We simply applied the above formulas

answer:

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explanation: