The compartments of these tanks are closed and filled with air. Gage A reads 207 kPa. Gage B registers a vacuum of 254 mm of mercury. What will gage C read if it is connected to compartment 1 but inside compartment 2

240.9 Kpa

Explanation:

Let first changes pressure Gage B from mm of mercury to KPa. That is,

254mm of mercury = 33.86KPa.

To calculate the pressure at C, we need to consider the atmospheric pressure and calculate the absolute pressure of the tank compartment

At gage C, the reading will read P1– P2

Where P1 = absolute pressure

Give that the pressure at B = 254 mm Hg

But (101.33/760) = 33.87 kPa

Where 101.33 = atmospheric pressure

Therefore,

P2 = 101 - 33.87 = 67.13 kPa

P2 = Pa ( pressure at A

Absolute P1 = Patm + Pa= 101 + 207 = 308 kPa abs.

Therefore, Pc = 308 - 67.13

Pc = 240.9Kpa

Therefore, gage C will read 240.9 Kpa if it is connected to compartment 1 but inside compartment 2

answer:

2d

explanation: