An aluminium bar 600mm long with a diameter 40mm has a hole drilled in the centre of which 30mm in diameter and 100mm long if the modulus of elasticity is 85GN/M2 calculate the total contraction oon the bar due to comprehensive load of 160KN.

Total contraction on the bar = 1.238 mm

Explanation:

Modulus of Elasticity, E = 85 GN/m²

Diameter of the aluminium bar,

Load, P = 160 kN

Cross sectional area of the aluminium bar without hole:

Diameter of hole,

Cross sectional area of the aluminium bar with hole:

Length of the aluminium bar,

Length of the hole,

Contraction in aluminium bar without hole  

Contraction in aluminium bar without hole  

Contraction in aluminium bar without hole = 96000/107100000

Contraction in aluminium bar without hole = 0.000896

Contraction in aluminium bar with hole  

Contraction in aluminium bar without hole  

Contraction in aluminium bar without hole = 16000/46750000

Contraction in aluminium bar without hole = 0.000342

Total contraction = 0.000896 + 0.000342

Total contraction = 0.001238 m = 1.238 mm

hes mad if he says,

explanation:

r!

answer:

understeer generally occurs when the front tyres start slipping while you go around the curve.

explanation:

hope it !