Engineering, 17.06.2020 12:57 melanie1055

A 1000 mm wide steel sheet made of C35 is normalized by cold rolling 10 mm thick deformed to 5 mm. The rollers, 600 mm in diameter, run at a peripheral speed of 0.12 m/s.
The deformation efficiency is 55%.
Find out:
a) the roller force
b) the roller torque
c) the performance on the pair of rollers.

Answers: 3

Show answers

Answers

Answer from: nakeytrag

a. 20.265 MN

b. 0.555 MNm

c. 403.44 KW

Explanation:

Given:-

- The width ( w ) = 1000 mm

- Original thickness ( to ) = 10 mm

- Final thickness ( t ) = 5 mm

- The radius of the rollers ( R ) = 600 mm

- The peripheral speed of the roller ( v ) = 0.12

- Deformation efficiency ( ε ) = 55%

Find:-

a) the roller force ( F )

b) the roller torque ( T )

c) the performance on the pair of rollers. ( P )

Solution:-

- The process of flat rolling entails a pair of compressive forces ( F ) exerted by the rollers on the steel sheet that permanently deforms.

- The permanent deformation of sheet metal is seen as reduced thickness.

- We will assume that the compressive force ( F ) acts normal to the point of contact between rollers and metal sheet.

- The roll force ( F ) is defined as:

F =L*w*Y_a_v_g

Where,

L: The projected length of strip under compression

Y_avg: The yielding stress of the material = 370 MPa

- The projected length of strip under compression is approximated by the following relation:

$L = \sqrt{R*( t_o - t_f )} \\\\L = \sqrt{0.6*( 0.01 - 0.005 )} \\\\L = 0.05477 m$

- The Roll force ( F ) can be determined as follows:

$F = (0.05477)*(1 )*(370*10^6 )\\\\F = 20.265 MN$

- The roll torque ( T ) is given by the following relation as follows:

$T = \frac{L}{2} * F\\\\T = \frac{0.05477}{2} * 20.265\\\\T = 0.555 MNm$

- The rotational speed of the rollers ( N ) is determined by the following procedure:

$f = \frac{v}{2\pi* R} = \frac{0.12}{2*\pi 0.6} = 0.03181818 \frac{rev}{s} \\\\N = f*60 = 1.9090 rpm$

- The power consumed by the pair of rollers ( P ) is given by:

$P = \frac{2\pi * F * L * N}{e*60,000} KW \\\\P = \frac{2\pi * ( 20.265*10^6) * (0.05477) * (1.90909 ) }{60,000*0.55} KW\\\\P = 403.44 KW$

Answer from: Quest

d would be the most obvious choice to this question. leaders are supposed to herd their underlings like a shepherd to sheep. a leader should also listen to others when they are talking to one other to gain a better understanding of their mission and surroundings.

explanation:

Answer from: Quest

Mri is one what are your options anyway ?

Another question on Engineering

Engineering, 03.07.2019 14:10

Amass of m 1.5 kg of steam is contained in a closed rigid container. initially the pressure and temperature of the steam are: p 1.5 mpa and t 240°c (superheated state), respectively. then the temperature drops to t2= 100°c as the result of heat transfer to the surroundings. determine: a) quality of the steam at the end of the process, b) heat transfer with the surroundings. for: p1.5 mpa and t 240°c: enthalpy of superheated vapour is 2900 kj/kg, specific volume of superheated vapour is 0. 1483 m/kg, while for t 100°c: enthalpy of saturated liquid water is 419kj/kg, specific volume of saturated liquid water is 0.001043m/kg, enthalpy of saturated vapour is 2676 kj/kg, specific volume of saturated vapour is 1.672 m/kg and pressure is 0.1 mpa.

Answers: 3

Answer

Engineering, 04.07.2019 19:10

Apressure vessel with an r/t 20 cannot be treated as thin walled vessel. a)-trune b)- false

Answers: 3

Answer

Engineering, 06.07.2019 02:30

An electric motor is used to drive a power press which makes steel turning moment diagrams 323 pressings from a metal sheet. the motor runs at a mean speed of 50 rev/s. the torque required is 10.0nm for 0.2s, followed by 1.0nm for0.3 s with this sequence then being repeated. what is the minimum power required of the motor and the moment of incrtia required for the t1ywhcel if the speed fluctuations are to be restricted to 1.5%?

Answers: 3

Answer

Engineering, 06.07.2019 03:10

Consider two concentric spheres forming an enclosure with diameters of 12 cm and 18 cm the spheres are maintained at uniform temperatures ti-50°c and t2 = 250°c and have emissivities .45 and .8, respectively. determine the net rate of radiation heat transfer between the two spheres per unit surface area.

Answers: 1

Answer

You know the right answer?

A 1000 mm wide steel sheet made of C35 is normalized by cold rolling 10 mm thick deformed to 5 mm....

Questions