Initially when 1000.00 mL of water at 10oC are poured into a glass cylinder, the height of the water column is 1000.00 mm. The water and its container are heated to 70oC. Assuming no evaporation, what then will be the depth of the water column if the coefficient of thermal expansion for the glass is 3.8*10-6 mm/mm peroC ?

Explanation:

Given that :

The initial volume of water = 1000.00 mL = 1000000 mm³

The initial temperature of the water   = 10° C

The height of the water column h = 1000.00 mm

The final temperature of the water = 70° C

The coefficient of thermal expansion for the glass is  ∝ =

The objective is to determine the the depth of the water column

In order to do that we will need to determine the volume of the water.

We obtain the data for physical properties of water at standard sea level atmospheric from pressure tables; So:

At temperature  the density of the water is

At temperature  the density of the water is

The mass of the water is  

Thus; we can say ;

⇒

Thus, the volume of the water after heating to a required temperature of   is 1022400 mm³

However; taking an integral look at this process; the volume of the water before heating can be deduced by the relation:

The area of the water before heating is:

The area of the heated water is :

Finally, the depth of the heated hot water is:

Hence the depth of the heated hot  water is

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answer:

the answer is d

explanation: