Q2: Determine the number of 8-inch-high by 8-inch-wide by 16-inch-long concrete blocks required to complete the wall in Figures below. The overhead doors are 10 feet wide by 12 feet high. If lintel blocks are required wherever the #4 horizontal bars are located and above the doors, how many plain blocks and how many lintel blocks are needed for the wall?

The image of the elevation and wall section is missing, so i have attached them.

Number of concrete blocks = 1020 blocks

Number of lintel blocks = 240

Number of plain blocks = 780

Explanation:

First of all, we'll find the net area of the wall as follows:

The height of the wall is 17' - 4", so we need to convert it to ft, thus, h = 17' + (4/12)' = 17.33'

So, Gross wall area = 80′ × 17.333' = 1,387 ft²

From the image, there are 4 doors, thus, Area of doors = 4 × 10′ × 12′ = 480 ft²

Thus, Net area = Gross wall area - area of doors

Net area = 1,387 – 480 = 907 ft²

We are told that the block is 8 inches length by 16inches width. Thus, converting to ft; (8/12)ft by (16/12)ft.

So area of one block = (8/12) x (16/12) = 128/144 ft² = 0.88889 ft²

So, number of blocks per ft² = 1/0.88889 = 1.125 blocks

So, there are 1.125 blocks per ft²

Thus, Number of concrete blocks = 907 ft² × 1.125 blocks per ft² = 1,020 blocks

From the image attached, there are five rows of lintel blocks, located at 4′, 8′, 12′, 16′, and 17′-4″. The bottom three rows pass through the doors and are only a total of (80′ – (4 × 10′) ) = 40′ long .

The top two rows are 80′ long. Thus, there is 40 feet (4 × 10′) of lintel block above the doors.

Lintel blocks = (3 × 40′) + (2 × 80′) + 40′ = 320 ft

Number of Lintel blocks = 320′ × 12 in per ft / 16″ = 240 blocks

Number of Plain blocks = 1,020 blocks – 240 blocks = 780 blocks

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