An infinite conducting cylindrical shell has radius 0.35 m and surface charge density 1.6 μC/m2. What is the magnitude of the electric field, in newtons per coulomb, 1.3 m from the axis of the cylinder?

The magnitude of the electric field is 8504 N/C

Explanation:

 rc = 0.35 m, Ac = 2πr^2 = 2 x π x 0.35^2 = 0.769 m^2, σ = 1.6 μC/m2 = 0.0000016 μC/m2

Surface Charge Density = total charge / surface area cylinder

σ = q / A ⇒ q = σ · A

q = 0.0000016 x 0.769

q = 1.23 μC

r = 1.3 m, k = 8.988 x 10^9

electric field vector = Coulomb constant * charge ÷ distance from charge

E = k * q ÷ r

E = 8.988 x 10^9 x 1.23 x 10^(-6) ÷ 1.3

E = 8504 N/C

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explanation:

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