Results of a standard compaction test (mold volume 943.9 cm3 ) are:

Trial No. 1 Mass of soil + mold 5619g
Mass of mold 3735g
Water content test
Mass of sample + container 288.26g
Mass of dry sample + container 265.39g
Mass of container 104.31g

Trial No. 2 Dry density 1795 kg/m^3 w=14.9%
Trial No. 3 Dry density 1828 kg/m^3 w=15.6%
Trial No. 4 Dry density 1832 kg/m^3 w=16.5%
Trial No. 5 Dry density 1796 kg/m^3 w=17.6%

a. Complete the calculations for trial No. 1.
b. Draw the moisture-density curve using Excel or other spreadsheet programs. Include ZAV curves at w=16%, 17%, and 18%. (The relative density of the soil is 2.65.) Find the maximum dry density and the optimum water content.

You are making beer. the first step is filling the glass carboy with the liquid wort. the internal diameter of the carboy is 15 in., and you wish to fill it up to a depth of 2 ft. if your wort is drawn from the kettle using a siphon process that flows at 3 gpm, how long will it take to fill?

Which of the following ziegler nichols tuning methods the response of the controller to a step input should exhibit an s-shaped curve? a)-open loop mode b)-closed loop mode c)-both modes (open & closed) d)-none of the modes (open & closed)

An external consultant recommends that a plant installs a bank of capacitors for power factor correction. this will reduce the peak electrical demand charges by an average of 93 kw every month. the plant current pays $13 per kw in peak demand charges. the capacitor bank will include 223 kw of fixed capacitors, and 183 of variable capacitors. the fixed capacitors cost $59 per kw, and the variable capacitors will cost $65 per kw. the consultant charges 21% of the equipment costs to install the capacitors. because this project will reduce the demand for the electric utility, they are prepared to provide a one-time rebate of $42 per kw of reduced demand. what is the simple payback period for this project (in years)?