Biologists use a sequence of letters A, C, T, and G to model a genome. A gene isa substring of a genome that starts after a triplet ATG and ends before a tripletTAG, TAA, or TGA. Furthermore, the length of a gene string is a multiple of 3and the gene does not contain any of the triplets ATG, TAG, TAA, and TGA. Write a program that prompts the user to enter a genome and displays all genesin the genome. If no gene is found in the input sequence, the program displays nogene is found. Here are sample runs of the program:Enter a genome string: a genome string: TGTGTGTATATno gene is found

You did not mention the programming language for implementation so i am writing a JAVA code.

import java.util.Scanner; // to get input from user

public class Genome{

public static void main(String[] args) { //start of main() function body

Scanner input = new Scanner(System.in); //creates Scanner object

System.out.print("Enter a genome string: ");

//prompts user to enter a genome string

String genome = input.nextLine();

//reads the input genome string and stores it into genome variable

boolean gene_found = false;

//variable gene_found of boolean type that has two value true or false

int startGene = 0; // stores starting of the gene string

for (int i = 0; i < genome.length() - 2; i++) {

//loop moves through genome string until the third last gene character

String triplet = genome.substring(i, i + 3);

//stores the triplet of genome substring

if (triplet.equals("ATG")) {

//if value in triplet is equal to ATG

startGene = i + 3;

//3 is added to i-th position of the genome string

}

else if (((triplet.equals("TAG")) || (triplet.equals("TAA")) || (triplet.equals("TGA"))) &&(startGene != 0))

//checks if the genome ends with one the given triplets TAG TAA and TGA

{ String gene = genome.substring(startGene, i);

gene stores substring of genome string from startGene to the position i

if (gene.length() % 3 == 0)

//if the the mod of gene length is 0 then the gene is found

{gene_found = true;

System.out.println(gene); //returns the found gene

startGene = 0;} } }

if (!gene_found) //if gene is not found returns the message below

System.out.println("no gene is found");}  }

Explanation:

This program first asks user to enter a genome string.

The loop starts from the first character of the entered string and this loop continues to execute until the value of i is 2 less than the genome input string length.

triplet variable stores first 3 characters of the genome string in first iteration and then moves through the string taking 3 characters each. This is done by dividing genome string to substring of 3 characters.

If condition checks if the 3 characters of genome string matches ATG using equals() function. If it is true this means start of genome is reached and these triplets are stored in startGene.

Else condition checks the end of the genome as the genome ends before one of TAG, TAA or TGA triplets. So this is checked here.

gene variable holds the triplet value stored in startGene and the value stored in index position i which means it holds the start of the genome till the end of the genome sequence. The end which is pointed by i variable is 2 less than the genome length and it is stored in gene variable.

After the loop ends the substring stored in gene variable is checked for a valid genome sequence by mod operator. If the length of the value stored in gene variable mod 0 is equal to 0 this means genome sequence is found and this string sequence stored in gene is displayed else the no gene is found message is displayed on output screen.

answer:

d. attempt to find the owner, then leave your information if you cannot find them.

explanation:

d. represents both (b) and (c).

more logical as well.

b and c are to complicated.

glad i could , give me a follow, so if you need with any other question, im here.