A specimen of aluminum having a rectangular cross section 9.6 mm × 12.4 mm (0.3780 in. × 0.4882 in.) is pulled in tension with 35000 N (7868 lbf) force, producing only elastic deformation. The elastic modulus for aluminum is 69 GPa (or 10 × 106 psi). Calculate the resulting strain.

0.00426

Explanation:

Young's modulus is given by the following expression,

where,

= Young's modulus

= force applied on the material

= cross-sectional area

= length of the material

= elongation due to stress applied

For our problem, we need to find the strain of the aluminum specimen,

Strain is a ratio and hence a dimensionless quantity, so even if calculate using the values in S.I. units, we shall get the same value.

can you make it more obvious. i can't see it properly

answer:

true

explanation: