Considering a closed, stationary, rigid container with certain gas inside, the total mass of the gas is 2 kg, and a heating process goes from state 1 with internal energy 100 kJ/kg to state 2 with internal energy 200 kJ/kg. Find the overall heat transfer into the system during the process.

The overall heat transfer is 200 kJ

Explanation:

Q = ∆U + W

Q is quantity of heat transfer

∆U is change in internal energy

W is work done

Assuming the process is an isometric process (constant volume) in which work done is 0

Therefore, Q = ∆U + 0

Q = ∆U

∆U = U2 - U1 = 200 - 100 = 100 kJ/kg

Total mass of gas = 2 kg

∆U = 100 kJ/kg × 2kg = 200 kJ

Q = 200 kJ

answer:

the answer is d

explanation: