Imagine the reaction A + B LaTeX: \Longleftrightarrow⟺ C + D proceeds at room temperature (25 °C) and is determined to have a reaction quotient (Q) equal to 46. If the equilibrium constant (Keq) for this reaction is equal to 35, what is the value of LaTeX: \DeltaΔG for this reaction in kcal/mol. Report your answer to the nearest tenth. Recall that to convert from °C to K you simply add 273 to the temperature in °C. In addition, the gas constant R is equal to 1.987 cal/KLaTeX: \cdot⋅mol. Be careful of units.

0.2 kcal/mol is the value of for this reaction.

Explanation:

The formula used for is:

where,

= Gibbs free energy for the reaction

=  standard Gibbs free energy  

R =Universal  gas constant

T = temperature

Q = reaction quotient

k = Equilibrium constant

We have :

Reaction quotient of the reaction = Q = 46

Equilibrium constant of reaction = K = 35

Temperature of reaction = T = 25°C = 25 + 273 K = 298 K

R = 1.987 cal/K mol

1 cal = 0.001 kcal

0.2 kcal/mol is the value of for this reaction.

sorry what a asnns

explanation:

answer:

31

explanation: