You are given a semiconductor resistor made from silicon with an impurity concentration of resistivity 1.00×10−3ωm1.00×10−3ωm. the resistor has a height of hh =0.5 , a length of ll = 2 , and a width of ww = 1.25 . the resistor can absorb (dissipate) up to pp = 7.81ww. what is the resistance of the resistor (rr), the maximum voltage (vv), and the maximum current (ii)?

The resistance (R) of the resistor is 2.4 ohm

The maximum voltage (V) is 4.33V

The maximum current (I) is 1.80A

Explanation:

Resistance (R) = resistivity×length/area

Resistivity = 0.003 ohm meter, length = 2mm = 2/1000 = 0.002m, width = 1.25mm = 1.25/1000 = 0.00125m, height = 0.5mm = 0.0005m, area = width × height = 0.00125m × 0.0005m = 6.25×10^-7m^2

R = 0.003×0.002/6.25×10^-7 = 3.2 ohm

Power (P) = V^2/R

V^2 = P × R = 7.81 × 3.2= 24.992

V = √24.992 = 4.99V

P = IV

I = P/V = 7.81/4.99 = 1.57A

answer:

a

explanation: