Atool chest has 950 n weight that acts through the midpoint of the chest. the chest is supported by feet at a and rollers at b. the surface has a coefficient of friction of 0.3. determine the value of the horizontal force p necessary to cause motion of the chest to the right, and determine if the motion is sliding or tipping. the value of p is n. the motion is .

P > 142.5 N  (→)

the motion sliding

Explanation:

Given

W = 959 N

μs = 0.3

If we apply

∑ Fy = 0 (+↑)

Ay + By = W

If  Ay = By

2*By = W

By = W / 2

By = 950 N / 2

By = 475 N (↑)

Then  we can get F (the force of friction) as follows

F = μs*N = μs*By

F = 0.3*475 N

F = 142.5 N (←)

we can apply

P - F  > 0

P  > 142.5 N (→)

the motion sliding

answer:

the formula for amps is watts divided by volts. to use the chart, cover up the a with your finger and use the remaining chart calculation of w divided by v. using our sample panel data, 60 watts divided by 12 volts equals 5 amps.

explanation:

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explanation: