If p=30 kpa and s= 6.983 kj/kg. find v, u & h.

v = 4.6275 m^3/kg

u = 2217.215 kJ/kg

h = 2356.0105 kJ/kg

Explanation:

Given data:

From steam table

At 30 Kpa

vf = 0.001022 m^3/kg          vg = 5.2287 m^3/kg

uf = 289.24 kJ/kg                  ufg = 2178.5 kJ/kg

hf = 289.27 kJ/kg                   hfg = 2335.3 kJ/kg

sf = 0.9441 kJ/kg K                  sfg = 6.8234  kJ/kg K

we know specific heat is given as

x = 0.885

v = 4.6275 m^3/kg

u = 2217.215 kJ/kg

h = 2356.0105 kJ/kg

oil flow is a highly convective flow compared to water flow at normal temperature and pressure.