A2.3-in-diameter steel rod 3 ft long is used between two immovable (rigid) walls. the rod is welded to the two walls at each of its two ends. the ambient temperature increases by 123 °f. the modulus of elasticity for the steel is 29 x 10^6 psi and the ctf is 4.0 x 10^-6/f. calculate the force exerted by the rod on the walls

F = 59250 pounds

Explanation:

given data;

Diameter = 2.3 inch

length = 3 ft = 36 inch

ambient temp = 73.4 degree F

cofficient of thermal expansion

We know that

F = 59250 pounds

answer:

okay

explanation:

answer:

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