Water is poured into a bucket according to the rate f of t equals the quotient of 7 plus t and the quantity 2 plus t , and at the same time empties out through a hole in the bottom at the rate e of t equals the quotient of the natural log of the quantity t plus 4 and the quantity t plus 2 , with both f(t) and e(t) measured in pints per minute. how much water, to the nearest pint, is in the bucket at time t = 5 minutes? you must show your setup, but can use your calculator for all evaluations.

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

                                                     sinserly Natalie 7 grader (this is not that hard)