How much power would you need to cool down a closed, 1 liter container of water from 100°c to 20°c in 5 minutes? (a) 1.1w (b)1.1kw (c)67kw (d)334 kj

The power required to cool the water is 1.11Kw.

Hence the correct option is (b).

Explanation:

Power needed to cool down is equal to heat extract from the water.

Given:

Volume of water is 1 liter.

Initial temperature is 100C.

Final temperature is 20C.

Time is 5 minutes.

Take density of water as 100 kg/m3.

Specific heat of water is 4.186 kj/kgK.

Calculation:

Step1

Mass of the water is calculated as follows:

m=1kg

Step2

Amount of heat extraction is calculated as follows:

Q=334880 j.

Step3

Power to cool the water is calculated as follows:

P=1116.26W

or

P=1.11 Kw.

Thus, the power required to cool the water is 1.11Kw.

Hence the correct option is (b).

x+2 because it just doubles hon so the pattern can actually tell you the expression.

so for example,

if x=2 then 2+2 is 4

if x=4 then 4+4 is 8

and so on and so forth.

i really hope that this makes sense and you out in a way hon: )

answer:

on fri feb the green land, the only one who can