If the equation for the velocity profile is given by: v = 4y^2/3. assuming v is in ft/s, what is the velocity gradient at the boundary and at y=0.25 ft and 0.5 ft from boundary?

At y = 0.25 ft velocity gradient will be 1.5866

At y = 0.5 ft velocity gradient will be 1.257

Explanation:

We have given velocity

We have to find velocity gradient

Velocity gradient is nothing but rate of change of velocity

So velocity gradient

(a) Now velocity gradient at y = 0.25 ft

(b) Velocity gradient at y = 0.5 ft

answer:

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explanation: