An ac power generator produces 50 a (rms) at 3600 v. the voltage is stepped up to 100 000 v by an ideal transformer and the energy is transmitted through a long-distance power line which has a resistance of 100 ohms. what percentage of the power delivered by the generator is dissipated as heat in the long-distance power line?

Given:

voltage, V = 3600V

step-up voltage, V' = 100000 V

Resistance of line,

Solution:

To calculate % heat loss in long distance power line:

Power produced by AC generator, P = W

P = 180000 W = 180 kW

At step-up voltage, V = 100000V or 100 kV

current, I =

I =

I = 1.8 A

Power line voltage drop is given by:

Power dissipated in long transmission line

Power dissipated in long transmission line = 324 W

% Heat loss in power line,

% Heat loss in power line,

answer:

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