Arigid tank (volume constant) contains 1.2 lbm of r-134a, initially at 90 psia and 160 f. the fluid is then cooled to a final temperature of 50 °f a) calculate the final pressure b) calculate the amount of thermal energy (heat) removed during the cooling process

(a) 74.023 psi (b) 133.4 KJ

Explanation:

We have given m=1.2 lbm

p₁=90 psi

T₁=160°F=459.67+160=619.67

T₂=50°F=459.67+50=509.67

(a) We know that for constant volume pressure is directly proportional to temperature

=

=

P₂=74.023 psi

(b) for R-134a

At P₁=90 psi ,T₁=160°F

h₁=458.658 KJ/KG (from the table)

At P₂=74.023 psi, T₂=50°F

h₂=219.593b (from the table)

m=1.2 lbm=.5443 kg

Q=.5443 ×(458.658-213.533)

Q=133.4 KJ

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