A14 (single shell pass, four tube-side passes) heat exchanger is to be designed to heat liquid from 300 k to 370 k. the heating medium enters the shell-side at 430 k and leaves at 380 k. if 10 kg/s of cold liquid is supplied, find the heat transfer area required and suggest a suitable tube arrangement. if the hot fluid outlet temperature drops to 360 k, is the design method still valid? if not, why not?

answer:

(b)

explanation:

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answer: Yes

Explanation:

answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

//main function

int main()

{

  // variable

 int n;

 cout<<"enter a number:";

 // read the input

 cin>>n;

 // find the square root of the absolute value

 float square_root=sqrt(abs(n));

 // print the square_root

 cout<<"square root of "<<n<<" is: "<<square_root<<endl;

  return 0;

}

Explanation:

Read a number from user and assign it to "n".Then find its absolute value with abs() function.Then calculate the square root of the absolute value with sqrt() function.Print the square root of the number.

Output:

enter a number:-17

square root of -17 is: 4.12311

                                                         This is easy

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