Au-tube manometer with both ends open, contains 0.35 m of oil on its left limb with an interface with water below it. if the water level on the right limb is 0.28 m above the interface, what is the sg of oil?

0.8

Explanation:

Given:

= 0.35m

= 0.28m

Equating the pressure in the manometer at both ends

we have

Pressure at the left limb = Pressure at right limb

substituting the values in the above equation, we get

we know that specific gravity is defined as the ratio of the density of the fluid with respect to the density of water

thus, SG of oil = 0.8

answer:

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answer:

explanation:

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