Write a program that calculates the cost of a phone call. the user enters a positive integer that indicates the length of the call. the first two minutes of a phone call cost a flat $1.50. minutes 3 to 10 cost 50 cents each. each minute after 10 costs 25 cents each. for example: how many minutes is the call? 13 a 13 minute call costs 6.25 my code so far: import java. util. scanner; public class third { public static void main (string[]args) { scanner num = new scanner (system. in); system. out. println("enter number of minutes"); int x = num. nextint(); i have gotten this far but im not sure what the rest is and how i would create the code for adding minutes. i know it has to do with final but not sure where to start.

Add the following constants in the class definition, before the main method:

    private final static float START_COST = 1.5f;
    private final static float HIGH_TARIFF = 0.5f;
    private final static float LOW_TARIFF = 0.25f;
    private final static int FIXED_MINS = 2;
    private final static int HIGH_TARIFF_MINS = 10;

Then add this to the main method you already had:

        float price = START_COST;
        if (x > FIXED_MINS) {
            if (x <= HIGH_TARIFF_MINS) {
                price += HIGH_TARIFF*(x-FIXED_MINS);
            }
            else {
                price += HIGH_TARIFF*(HIGH_TARIFF_MINS-FIXED_MINS) 
                    + LOW_TARIFF*(x-HIGH_TARIFF_MINS);
            }
        }   
        System.out.printf("A %d minute call costs %.2f", x, price);      

Aphone operater

The answer for your specific question is d.