Write code that assigns maxValue with the return value of calling the function GetMaxValue passing userNum1 and userNum2 as arguments (in that order). Then, assign maxValue with the return value of calling GetMaxValue passing maxValue and userNum3 as arguments (in that order). Function GetMaxValue(integer value1, integer value2) returns integer result
if value1 > value2
result = value1
else
result = value2
Function Main() returns nothing
integer userNum1
integer userNum2
integer userNum3
integer maxValue
userNum1 = Get next input
userNum2 = Get next input
userNum3 = Get next input
// Your solution goes here
Put "Max value: " to output
Put maxValue to output
has to be in Coral

Create a function (prob3_6) that will do the following: input a positive scalar integer x. if x is odd, multiply it by 3 and add 1. if the given x is even, divide it by 2. repeat this rule on the new value until you get 1, if ever. your program will output how many operations it had to perform to get to 1 and the largest number along the way. for example, start with the number 3: because 3 is odd, we multiply by 3 and add 1 giving us 10. 10 is even so we divide it by 2, giving us 5. 5 is odd so we multiply by 3 and add one, giving us 16. we divide 16 (even) by two giving 8. we divide 8 (even) by two giving 4. we divide 4 (even) by two giving 2. we divide 2 (even) by 2 to give us 1. once we have one, we stop. this example took seven operations to get to one. the largest number we had along the way was 16. every value of n that anyone has ever checked eventually leads to 1, but it is an open mathematical problem (known as the collatz conjectureopens in new tab) whether every value of n eventually leads to 1. your program should include a while loop and an if-statement.