Complete the truth table for the following logic circuit.

A  B   X

0   0   0

0   1    1

1    0   1

1    1    1

Explanation:

If A=1, the output X is 1 as well, due to the OR gate. So that takes care of the last two rows.

If B=0, the AND gate will be 0 so it cannot contribute to X becoming 1. So that takes care of the first row (X=0).

For A=0, B=1, the AND gate will be 1, so X will be as well. You can see that the truth table matches that of a simple OR gate, X=A+B

Rather than exercising the circuit like this, you can also find this outcome algebraically:

X = (A + (A' * B)) [apply distributive law]

X = (A + A')*(A + B) [complement law]

X = 1 * (A + B)

X = A + B

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