Create a function that takes an integer array as input and a value and returns a POINTER to the number of times the value appears in the integer array, zero if it does not appear in the array. Use pointer arithmetic to work through the array (don't use the [ ] operator)

How to print: number is equal to: 1 and it is odd number number is equal to: 2 and it is even number number is equal to: 3 and it is odd number number is equal to: 4 and it is even number in the console using java using 1 if statement, 1 while loop, 1 else loop also using % to check odds and evens

Whose task it is to ensure that the product flows logically from one step to another?

Into what form does the barcode reader convert individual bar patterns?