C++Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in an expression.#include using namespace std;double FindMax(double num1, double num2) { double maxVal; // Note: if-else statements need not be understood to complete this activity if (num1 > num2) { // if num1 is greater than num2, maxVal = num1; // then num1 is the maxVal. } else { // Otherwise, maxVal = num2; // num2 is the maxVal. } return maxVal;}int main() { double numA; double numB; double numY; double numZ; double maxSum; cin >> numA; cin >> numB; cin >> numY; cin >> numZ; /* Your solution goes here */ cout << "maxSum is: " << maxSum << endl; return 0;}